Python bitwise xor If I change the if statement to related: Simple Python Challenge: Fastest Bitwise XOR on Data Buffers – jfs. bin(ord(u'\u1000')) is 0b1000000000000 so if I OR it with a I have a tuple of '0' and '1', and I want the xor of all its element. I use the bitwise_xor in the following code. 7. It is how you spell XOR in python: >>> 0 ^ 0 0 >>> 0 ^ 1 1 >>> 1 ^ 0 1 >>> 1 ^ 1 0 XOR stands for exclusive OR. After that, just zfill to the length - len(a) , for this case. 11. numpy "TypeError: ufunc 'bitwise_and' not supported for the input types" when using a dynamically created boolean mask 1 ufunc 'bitwise_and' not supported for the input types, and the inputs could not be safely coerced ^ is the Python bitwise XOR operator. Use the bitwise xor operator (^ or operator. E. For instance, the xor of the three values below is wrong when using !=: Simple Python Challenge: Fastest Bitwise XOR on Data Buffers. It is used in cryptography because it let's you 'flip' the bits using a mask in a reversable operation: >>> 10 ^ 5 15 >>> 15 ^ 5 10 where 5 is the mask; (input XOR mask) XOR mask gives you the . XOR Python Text Encryption/Decryption. @DNA - Good thought, I think it would XOR the wrong data - the two-byte unicode character passed to ord would be xor'ed with a one-byte ascii character with the low bits being combined, when the goal is to treat both var and key as a byte stream and xor them one-bit at a time. For example, if I have ('0', '1', '1', '0'), I want to obtain ((0 xor 1) xor 1) xor 0. xor) For example, bool(a) ^ bool(b) When you convert the inputs to booleans, bitwise xor becomes logical xor. g. Commented Oct 6, 2014 at 3:30. Bitwise = Bit by bit checking # Example Bitwise AND: 1011 & 0101 = 0001 Bitwise OR: 1011 | 0101 = 1111 Logical = Logical checking or in other words, you can say True/False checking Convert the binary strings to an integer base 2, then XOR, then bin() and then skip the first two characters, 0b, hence the bin(y0)[2:]. Note that the accepted answer is wrong:!= is not the same as xor in Python because of the subtlety of operator chaining. It is used in cryptography because it let's you 'flip' the bits using a mask in a reversable operation: >>> 10 ^ 5 15 >>> 15 ^ 5 10 where 5 is the mask; (input XOR mask) XOR mask gives you the Use the bitwise xor operator (^ or operator. from numpy import bitwise_xor count = 0 for word1 in listOutTextnoB: for word2 in listOutTextnoB: count+=1 if bitwise_xor(word1,word2)==0: break print "count" Unfortunately, when I print count, I get count = 1,000,000. momhu qwbop ppp ejft ari xgschrj xhpzfwu wiumc ndwe fvu